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Section Chapter 8 Exercises

Reading Questions α―“β˜…β“ Quick-Answer Questions

1. Multiple-Choice.

(a) Modifying the Initial Guess.
When solving \(y'' - 2y' + y = e^x\text{,}\) the initial guess for \(y_p\) is modified to \(Ax^2 e^x\) because \(e^x\) overlaps with .
  • \(c_1 e^x\)
  • \(c_2 x^2 e^x\)
  • \(y_h\)
  • \(c_1 \cos(x)\)
(b) Purpose of the Method.
What is the main purpose of the Method of Undetermined Coefficients?
  • To solve the homogeneous solution \(y_h\) directly.
  • To determine the coefficients in the particular solution \(y_p\text{.}\)
  • To find the characteristic equation roots.
  • To verify initial conditions are satisfied.
(c) When It Works.
The Method of Undetermined Coefficients applies when \(f(x)\) is:
  • A polynomial, exponential, sine, or cosine function.
  • A logarithmic function like \(\ln x\text{.}\)
  • A tangent function like \(\tan x\text{.}\)
  • A sum or product of polynomials, exponentials, and trig functions.
(d) Choose \(y_p\).
Suppose
\begin{equation*} y'' - 4y' + 3y = 6e^x\text{.} \end{equation*}
Which of the following is the correct selection for \(y_p\text{?}\)
  • \(\ds\quad y_p = Ae^x\)
  • Incorrect. Remember to consider whether \(e^x\) overlaps with any terms in \(y_h\text{.}\)
  • \(\ds\quad y_p = Axe^x\)
  • Correct! Since \(e^x\) is a term in \(y_h\text{,}\) we need to multiply the particular solution by \(x\) to ensure independence.
  • \(\ds\quad y_p = Ax + B\)
  • Incorrect. This form is more suited for a polynomial right-hand side like \(f(x) = 6x\text{.}\)
  • \(\ds\quad y_p = A\)
  • Incorrect. A constant form of \(y_p\) would only be appropriate if \(f(x)\) were a constant.
(e) Selecting the particular form.
Select the initial form of the particular solution for an LNCC equation with forcing function:
\begin{equation*} f(x) = 5x^2 + 3x\text{.} \end{equation*}
  • \(\ds\quad y_p = Ax^2 + Bx + C\)
  • Correct! Since the forcing function is a 2nd degree polynomial, the particular solution should be the most general 2nd degree polynomial.
  • \(\ds\quad y_p = A e^{x} + B\)
  • Incorrect. The forcing function does not contain an exponential function, so neither should the particular solution.
  • \(\ds\quad y_p = A x^2 + B x\)
  • Incorrect. This form is missing a free term.
  • \(\ds\quad y_p = Ax^3 + Bx^2 + Cx + D\)
  • Incorrect. While this form technically works, the \(x^3\) term is unnecessary and makes the problem more difficult.
(f) Select the correct form.
What is the most appropriate form for the particular solution to
\begin{equation*} y'' - 4y' + 3y = 9x + 6\text{?} \end{equation*}
  • \(\ds\quad Ax + B\)
  • Correct! The forcing function is a first degree polynomial, so the particular solution should generalize this form as \(Ax + B\text{.}\)
  • \(\ds\quad Ae^{9x}\)
  • Incorrect. The forcing function is a polynomial, not an exponential function.
  • \(\ds\quad A\sin(9x)\)
  • Incorrect. The forcing function is a polynomial, not a trigonometric function.
  • \(\ds\quad A\)
  • Incorrect. The forcing function is not a constant.
(g) Classifying Practice.
Select each classification label that applies to the equation
\begin{equation*} y'' = y' + 6y \end{equation*}
  • Linear
  • Correct, each of the terms are linear.
  • Homogeneous
  • Correct, the free term is zero.
  • Constant Coefficients
  • Correct, each coefficient is constant.
  • LHCC
  • Correct!
(h) Classifying Practice.
Select each classification label that applies to the equation
\begin{equation*} 3y''' + y'- \sin(y) = 0 \end{equation*}
  • Linear
  • Incorrect, \(\sin(y)\) is a nonlinear term.
  • Homogeneous
  • Technically, only linear equations can be labeled as homogeneous or not. Since the equation is nonlinear, we do not select it.
  • Constant Coefficients
  • Technically, only linear equations can be labeled as having constant coefficients or not. Since the equation is nonlinear, we do not select it.
  • LHCC
  • Incorrect.
(i) Classifying Practice.
Select each classification label that applies to the equation
\begin{equation*} y''- 6 = 0 \end{equation*}
  • Linear
  • Correct, both terms are linear.
  • Homogeneous
  • Incorrect, the free term, \(6\text{,}\) is non-zero.
  • Constant Coefficients
  • Correct, each coefficient is constant.
  • LHCC
  • Incorrect.
(j) Classifying Practice.
Select each classification label that applies to the equation
\begin{equation*} \frac{d^3y}{dt^3} + k\frac{dy}{dt} = ty, \qquad k \text{ is constant} \end{equation*}
  • Linear
  • Correct, all terms are linear.
  • Homogeneous
  • Correct, the free term is zero.
  • Constant Coefficients
  • Incorrect, the \(y\) term coefficient, \(t\text{,}\) is not constant.
  • LHCC
  • Incorrect.

2. Short-Answer.

(a)
Suppose you knew that the final form of the particular solution of an LHCC equation was \(y_p = Axe^x \text{.}\) Using only this information, list out everything you can deduce about the differential equation.
(b) Why do we modify the particular solution \(y_p\) by multiplying it by \(x\) when solving LNCC equations?
Why do we modify the particular solution \(y_p\) by multiplying it by \(x\) when solving LNCC equations?
(c) In the general solution of an LNCC equation, what roles do \(y_h\) and \(y_p\) play, and why is it important that they are independent?
In the general solution of an LNCC equation, what roles do \(y_h\) and \(y_p\) play, and why is it important that they are independent?
(d)
Describe the difference between a homogeneous and a non-homogeneous differential equation.

Exercises πŸ—οΈ Warm-ups & Drills

Write Down the Form of \(y_p\).

For each forcing function \(g(t)\text{,}\) write down the correct form of the particular solution \(y_p\text{.}\) Don’t solve for coefficients, just show the form of \(y_p\text{.}\)
2.
\(g(t) = 6t^2 - 7\sin(3t) + 9\)
3.
\(g(t) = 10e^t - 5t e^{-8t} + 2 e^{-8t}\)
4.
\(g(t) = t^2\cos t - 5t\sin t\)
6.
\(g(t) = (9t^2 - 103t)\cos t\)
7.
\(g(t) = - e^{-2t}(3 - 5t)\cos(9t)\)
8.
\(g(t) = 4\cos(6t) - 9\sin(6t)\)
9.
\(g(t) = - 2\sin t + \sin(14t) - 5\cos(14t)\)
10.
\(g(t) = 5e^{-3t} + e^{-3t}\cos(6t) - \sin(6t)\)

Find the Initial Form of \(y_p\).

For each differential equation below, determine the correct form of the particular solution \(y_p\text{.}\) Do NOT solve for coefficients like \(A, B, C\text{.}\)
11.
\(3z'' - 4z' - 12z = 17 + 2\cos(2\theta)\)
12.
\(y'' - 3y' - 17y = x^2 + \cos x \)
13.
\(y'' + y' - 12y = 4e^{3t} + \cos(2t) \)
14.
\(y'' - 4y = 2t - e^{2t}\sin(3t) \)
15.
\(w'' - 4w' + 13w = e^{3x} + x^2e^{-x} \)
16.
\(y'' - 2y' + y = x^2 + e^x \)
17.
\(z'' - 4z' + 5z = te^{2t} + 2e^{2t}\sin t \)
18.
\(x^3 \sin(4x) + x^2 \sin(4x) + 7y'' - y' + 2y = 0\)

Particular Solution.

In these exercises, go one step beyond identifying the form of \(y_p\) and actually solve for the coefficients and write down a particular solution.
Remember:
  • Find \(y_c\) first, to identify duplicates.
  • Guess \(y_p\) based on the forcing term.
  • Modify \(y_p\) if there’s overlap with \(y_c\text{.}\)
  • Plug into the DE, solve for the coefficients, and write the final \(y_p\text{.}\)
19.
\(y'' - 4y' - 12y = 3e^{5t}\)
20.
\(y'' - 4y' - 12y = \sin(2t)\)
21.
\(y'' - 4y' - 12y = 2t^3 - t + 3\)
22.
\(y'' - 4y' - 12y = e^{6t}\)

Exercises ✍🏻 Solve the Differential Equations

General Solutions – Method of Undetermined Coefficients.

Find the general solution to each differential equation using the five-step Method of Undetermined Coefficients:
  1. Find the homogeneous solution \(y_h\text{.}\)
  2. Guess a form for \(y_p\) based on the forcing function.
  3. Modify \(y_p\) if it overlaps with \(y_h\text{.}\)
  4. Substitute \(y_p\) into the DE and solve for coefficients.
  5. Write the general solution \(y = y_h + y_p\text{.}\)
3.
\(y'' - 4y' - 5y = t + 2e^{-t}\)
4.
\(z'' - 6z' + 34z = 650 \sin(6x)\)
5.
\(y'' - 4y' + 4y = 8\cos x + 12 e^{2x}\)
6.
\(y'' - y' - 6y = 2t + 3e^{3t} - e^{-2t}\)
8.
\(y'' - 3y' + y = 2x^2 + 3x\)
9.
\(y'' - 4y' - 12y = t e^{4t}\)
11.
\(y'' + 3y' - 28y = 7t + e^{4t} - 1\)
12.
\(y'' - 100y = 9 t^2 e^{10t} + \cos t - t \sin t\)
13.
\(4y'' + y = e^{-2t} \sin \left( \frac{t}{2} \right) + 6 t \cos \left( \frac{t}{2} \right)\)
14.
\(4y'' + 16y' + 17y = e^{-2t} \sin \left( \frac{t}{2} \right) + 6 t \cos \left( \frac{t}{2} \right)\)
15.
\(y'' + 8y' + 16y = e^{-4t} + (t^2 + 5)e^{-4t}\)

Initial Value Problems – Easy to Moderate.

These IVPs involve either first-order linear DEs or simpler second-order equations with single forcing terms. Follow the UC workflow:
  1. Find \(y_h\) (the homogeneous solution).
  2. Guess \(y_p\) (the particular solution).
  3. Adjust \(y_p\) if it overlaps with \(y_h\text{.}\)
  4. Substitute \(y_p\) and solve for coefficients.
  5. Write \(y = y_h + y_p\text{.}\)
  6. Apply initial condition(s) to find the specific solution.
16.
\(y' - 3y = 6,\quad y(0) = 5\)
17.
\(2x' + x = 3t^2,\quad x(0) = 15\)
18.
\(e^t z' = 1 - 4e^t z,\quad z(0) = \frac{4}{3}\)
19.
\(2z'' + z = 9e^{2t}, \ z(0)=3, \ z'(0)=-1\)

Initial Value Problems – Advanced.

These IVPs involve second-order DEs with multi-term forcing functions (polynomials, exponentials, trig). They require careful handling of overlaps and sometimes multiple adjustments to \(y_p\text{.}\)
20.
\(y'' - 4y' - 12y = 3 e^{5t}, \ y(0)=\frac{18}{7}, \ y'(0)=-\frac{1}{7}\)
21.
\(y'' - 4y' - 6y = 2t + 3e^{3t} - e^{-2t},\ y(0)=0, \ y'(0)=0\)
22.
\(4y'' + 16y' + 17y = e^{-2t} \sin \frac{t}{2} + 6 t \cos \frac{t}{2},\ y(0)=-1, \ y'(0)=0\)
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