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Section 5.3 Dividing by a Monomial

We learned how to add and subtract polynomials in Section 1. Then in [cross-reference to target(s) "section-introduction-to-exponent-properties" missing or not unique], we learned how to multiply monomials together (but not yet how to multiply general polynomials together). In this section we learn how to divide a general polynomial by a monomial.
Figure 5.3.1. Alternative Video Lesson

Subsection 5.3.1 Quotient of Powers Property

When we multiply the same base raised to powers, we add the exponents, as in 22โ‹…23=25. What happens when we divide the same base raised to powers?

Example 5.3.2.

Simplify x5x2 by first writing out what each power means.
Explanation.
Without knowing a property for simplifying this quotient of powers, we can write the expressions without exponents and simplify.
x5x2=xโ‹…xโ‹…xโ‹…xโ‹…xxโ‹…x=xโ‹…xโ‹…xโ‹…xโ‹…xxโ‹…xโ‹…1=xโ‹…xโ‹…x1=x3
Notice that the difference of the exponents of the numerator and the denominator (5 and 2, respectively) is 3, which is the exponent of the simplified expression.
When we divide as weโ€™ve just done, we end up canceling factors from the numerator and denominator one-for-one. These common factors cancel to give us factors of 1. The general rule for this is:
This rule says that when youโ€™re dividing two expressions that have the same base, you can simplify the quotient by subtracting the exponents. In Example 2, this means that we can directly compute x5x2:
x5x2=x5โˆ’2=x3
Now we can update the list of exponent properties from [cross-reference to target(s) "section-introduction-to-exponent-properties" missing or not unique].
List 5.3.4. Summary of the Properties of Exponents (Thus Far)
If a and b are real numbers, and m and n are positive integers, then we have the following properties:
Product Property
amโ‹…an=am+n
Power to a Power Property
(am)n=amโ‹…n
Product to a Power Property
(ab)m=amโ‹…bm
Quotient of Powers Property
aman=amโˆ’n (when m>n)

Subsection 5.3.2 Dividing a Polynomial by a Monomial

Recall that dividing by a number c is the same as multiplying by the reciprocal 1c. For example, whether you divide 8 by 2 or multiply 8 by 12, the result is 4 either way. In symbols,
82=12โ‹…8(both work out to 4)
If we apply this idea to a polynomial being divided by a monomial, say with a+bc, we can see that the distributive law works for this kind of division as well as with multiplication:
a+bc=1cโ‹…(a+b)=1cโ‹…a+1cโ‹…b=ac+bc
In the end, the c has been โ€œdistributedโ€ into the a and the b. Once we recognize that division by a monomial is distributive, we are left with individual monomial pairs that we can divide.

Example 5.3.5.

Simplify 2x3+4x2โˆ’10x2.
We recognize that the 2 weโ€™re dividing by can be divided into each and every term of the numerator. Once we recognize that, we will simply perform those divisions.
2x3+4x2โˆ’10x2=2x32+4x22+โˆ’10x2=x3+2x2โˆ’5x

Example 5.3.6.

Simplify 15x4โˆ’9x3+12x23x2.
Explanation.
We recognize that each term in the numerator can be divided by 3x2. To actually carry out that division weโ€™ll need to use the Quotient of Powers Property. This is going to cause a change in each coefficient and exponent.
15x4โˆ’9x3+12x23x2=15x43x2+โˆ’9x33x2+12x23x2=5x2โˆ’3x+4

Remark 5.3.7.

Once you become comfortable with this process, you might leave out the step where we wrote out the distribution. You will do the distribution in your head and this will become a one-step exercise. Hereโ€™s how Example 6 would be visualized:
15x4โˆ’9x3+12x23x2=5x2โˆ’3x1+4x0
And when calculated, weโ€™d get:
15x4โˆ’9x3+12x23x2=5x2โˆ’3x+4
(With the last term, note that x2x2 reduces to 1.)

Example 5.3.8.

Simplify 20x3y4+30x2y3โˆ’5x2y2โˆ’5xy2.
Explanation.
20x3y4+30x2y3โˆ’5x2y2โˆ’5xy2=20x3y4โˆ’5xy2+30x2y3โˆ’5xy2+โˆ’5x2y2โˆ’5xy2=โˆ’4x2y2โˆ’6xy+x

Checkpoint 5.3.9.

Simplify the following expression
18r20+18r16โˆ’54r14โˆ’6r2=
Explanation.
We divide each term by โˆ’6r2 as follows.
18r20+18r16โˆ’54r14โˆ’6r2=18r20โˆ’6r2+18r16โˆ’6r2+โˆ’54r14โˆ’6r2=โˆ’186r18โˆ’186r14+546r12=โˆ’3r18โˆ’3r14+9r12

Example 5.3.10.

The density of an object, ฯ (pronounced โ€œrhoโ€), can be calculated by the formula
ฯ=mV
where m is the objectโ€™s mass, and V is its volume. The mass of a certain cancerous growth can be modeled by 4t3โˆ’6t2+8t grams, where t is the number of days since the growth began. If its volume is 2t cubic centimeters, find the growthโ€™s density.
Explanation.
We have:
ฯ=mV=4t3โˆ’6t2+8t2tgcm3=4t32tโˆ’6t22t+8t2tgcm3=2t2โˆ’3t+4gcm3
The growthโ€™s density can be modeled by 2t2โˆ’3t+4 gโ„cm3.

Reading Questions 5.3.3 Reading Questions

1.

How is dividing a polynomial by a monomial similar to distributing multiplication over a polynomial? For example, how is the process of simplifying 15x3+5x2+10x5x similar to simplifying 5x(15x3+5x2+10x)?

Exercises 5.3.4 Exercises

Skills Practice

Quotient of Powers Property.
Use properties of exponents to simplify the expression.
Dividing Polynomials by Monomials.
Simplify the expression.

Applications

Exercise Group.
A rectangular prismโ€™s base area can be calculated by the formula B=Vh, where V is the volume and h is the height.
33.
A certain rectangular prismโ€™s volume can be modeled by 6x5+30x3+18x2 cubic units. If its height is 3x units, find the prismโ€™s base area.
34.
A certain rectangular prismโ€™s volume can be modeled by 24x4โˆ’16x3+12x2 cubic units. If its height is 4x units, find the prismโ€™s base area.
Exercise Group.
A cylinderโ€™s height can be calculated by the formula h=VB, where V is the volume and B is the base area.
35.
A certain cylinderโ€™s volume can be modeled by 18ฯ€x7โˆ’24ฯ€x5โˆ’27ฯ€x3 cubic units. If its base area is 3ฯ€x2 square units, find the cylinderโ€™s height.
36.
A certain cylinderโ€™s volume can be modeled by 9ฯ€x7โˆ’9ฯ€x4+27ฯ€x3 cubic units. If its base area is 3ฯ€x2 square units, find the cylinderโ€™s height.
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