18.6. Chapter Exercises¶
The exercises for this chapter use a different database than the rest of the chapter. The
movies database has two tables, movies and actors. We will be using the movie
table (so queries will look like SELECT * from movies). It features the following
columns of data:
Column Name |
Description |
|---|---|
id |
A unique number for each record |
imdb_id |
The id of the movie in the Internet Movie DataBase (IMDB) |
title |
Title fo the movie |
director |
Name of the director |
year |
Year (number) the movie was released |
rating |
Rating (R, PG, etc…) |
genre |
Comma separated list of genres |
runtime |
Length in minutes |
country |
Comma separated list of countries it was released in |
language |
Comma separated list of languages it was released in |
imdb_score |
Score of movie (1-10) in IMDB |
imdb_votes |
Number of ratings for the movie in the IMDB |
metacritic_score |
Score of movie (1-100) on the Metacritic website |
Write a query to find the average IMDB score for all the movies.
Write a query to find the highest IMDB score for any movie that was
directed at least partially by Quentin Tarantino. (Hint: A movie can have
multiple directors, so you will need to use director LIKE '%Quentin Tarantino%'
to identify movies where Quentin Tarantino is in the list of directors.)
Write a query to display the total number of movies with a rating of 'PG-13'
in the database.
Use GROUP BY to write a query to display each rating category with the
number of movies in that category. Your output should look like this:
... PG | 43 PG-13 | 32 ...
Write a query to list each director with the highest (MAX) imdb_score that director’s
movies have earned. Order the output so the directors with the highest imdb_score come first.
Hint: You will need to use both GROUP BY and ORDER BY`.
Your output should look like this:
director | score Frank Darabont | 9.3 Francis Ford Coppola | 9.2 ...
Write a query to list each director with the COUNT of the number of films they have made.
But only retrieve the data for directors with at least 2 films.
The results should be sorted by director’s name (but that should be the default,
you should not have to use ORDER BY).
Hint: Remember that you have to use HAVING to filter grouped results.
Your output should look like this:
director | num_films Akira Kurosawa | 5 Alfred Hitchcock | 6 ...
Write a query to list each director with the number of movies they have made that
have an imdb_score of 8.5 or higher.
Sort the results so the directors with the greatest number of highly rated files are first.
Hint: Here you want to filter the movies by IMDB rating before they are aggregated,
so you need a WHERE not a HAVING.
Your output should look like this:
director | high_rated_films Peter Jackson | 3 Christopher Nolan | 3 Steven Spielberg | 2 ...
The following problems will also make use of the actors table. It consists of records that
match a movie to a particular actor. If an actor appears in multiple movies, they will appear
in one record for each movie they appear in.
Column Name |
Description |
|---|---|
id |
A unique number for each record |
movie_id |
The id of the movie the actor appears in. This will match the |
imdb_id |
ID of the actor on the IMDB website |
name |
Name of the actor |
We would like to know the title of all the movies Marlon Brando acted in.
Write a query that gets just the movies.title from the results of
joining the actors table with the movies table
(so that actors.movie_id matches with movies.id) and
selecting rows in which the actors.name is "Marlon Brando".
Your output should look like this:
title Apocalypse Now On the Waterfront The Godfather
Write a query that displays each actor.name with the highest metacritic_score
of any movie that actor has been in (we won’t know what movie the score is from).
You will have to join actors and movies so that you have access to all the
needed data. You will also have to use GROUP BY. The GROUP BY should come after the
JOIN.
Your output should look like this:
name | max_metacritic A.B. Lane | 0 A.J. O'Connor | 0 A.K. Hangal | 84 A.R. Haysel | 87 A.S. Duggal | 67 ...
