10.8. Multiple Choice Questions

Q-1: Which line of code correctly adds an item to the fruits dictionary with a key of ‘grapes’ and a value of 15?

fruits = {'apples': 1, 'bananas': 4, 'pears': 17, 'oranges': 14}

• fruits['grapes']
• Try again! This does not add a value.
• fruits['grapes'] = 15
• Correct! This line adds 'grapes' as a key with a value of 15.
• insert 'grapes' in fruits
• Try again! This is not correct Python.
• fruits[15] = 'grapes'
• Try again! This sets the key to 15 and the value to 'grapes'.

Q-2: What does the following code print?

names = {'Janice': 5, 'Emily': 3, 'John': 7, 'Eleanor': 2}
list_o_names = []
for name in names:
    if names[name] > 5:
        list_o_names.append(name)
print(list_o_names)

• ['Janice', 'John']
• Try again! This would be true if it was greater than or equal 5.
• ['Janice', 'Emily', 'Eleanor']
• Try again! This only adds items with a value greater than 5.
• ['John']
• Correct! John is the only key that has a value greater than 5.
• ['Janice', 'Emily', 'John', 'Eleanor']
• Try again! This only adds items with a value greater than 5.

Q-3: What does the following code print?

names = {'Janice': 5, 'Emily': 3, 'John': 7, 'Eleanor': 2}
list_o_names = []

names['Emily'] += 10
names['Erik'] = 22

for name in names:
    if names[name] > 5:
        list_o_names.append(name)
print(list_o_names)

• ['Emily', 'John', 'Erik']
• Correct! Erik is initialized to 22, and Emily is updated to 13. Therefore, these two entries are added to the list found in the previous question.
• ['Janice', 'Emily', 'John']
• Try again! Erik is set to 22, so it should be added.
• ['Janice', 'John', 'Erik']
• Try again! Emily is set to 13, so it should be added.
• ['Janice', 'Emily', 'John', 'Eleanor']
• Try again! This will not add Eleanor since the value is 2, and this will not add Janice since the value is 5.

Q-4: What is the value of counter after the code is run?

phrase = "Cheese in Philadelphia is extraordinary according to Erik"

counter = 0
letters = {}
for word in phrase.split():
    for letter in word:
        letter = letter.lower()
        if letter not in letters.keys():
            letters[letter] = 0
        letters[letter] += 1
for key in letters.keys():
    if letters[key] > 2:
        counter += 1

• 5
• Try again!
• 10
• Try again!
• 9
• Correct! There are 9 letters in phrase that appear more than two times.

Q-5: Which line of code correctly gets the value of the key ‘apples’ if it exists and returns 0 if it does not?

fruits = {'bananas': 7, 'apples': 4, 'grapes': 19, 'pears': 4}

• fruits.get(apples)
• Try again! The key must be a string in this case.
• fruits.get('apples', 0)
• Correct! This correctly grabs the key as a string and also includes a default value in case the key is not present in the dictionary.
• fruits.get('apple')
• Try again! This will return None if the key does not exist.
• fruits.get(apples, 0)
• Try again! The key must be a string in this case.

Q-6: What value is printed when this code runs?

word = 'brontosaurus'
diction = {}
for letter in word:
    if letter not in diction.keys():
        diction[letter] = 0
    diction[letter] += 1
print(diction.get('o', 0) + 4)

• 10
• Try again!
• 4
• Try again!
• 6
• Correct! The get() method grabs the value 2 and then 4 gets added to it to get 6.
• 2
• Try again! This would be true if it just printed the value for the key 'o'. However, 4 is added to it.

Q-7: What order do the keys print in after the following code is run?

counts = {'annie' : 42, 'chuck' : 1, 'jan' : 100}
for key in counts:
    print(key)

• jan, chuck, annie
• The order is their order in the dictionary.
• chuck, annie, jan
• The order is their order in the dictionary.
• annie, chuck, jan
• Correct! The order is their order in the dictionary.
• jan, annie, chuck
• The order is their order in the dictionary.

Q-8: What order do the keys print in after the following code is run?

counts = {'annie' : 42, 'chuck' : 1, 'jan' : 100}
items = counts.items()
out = sorted(items, reverse = True)
for item in out:
    print(item[0])

• jan, chuck, annie
• Correct! This will sort by the keys in descending order.
• chuck, annie, jan
• This will sort by the keys in descending order.
• annie, chuck, jan
• This will sort by the keys in descending order.
• jan, annie, chuck
• This will sort by the keys in descending order.

Q-9: What order do the keys print in after the following code is run?

counts = {'annie' : 42, 'chuck' : 1, 'jan' : 100}
items = counts.items()
out = sorted(items, key = lambda t: t[1])
for item in out:
    print(item[0])

• jan, chuck, annie
• This will sort by the values in ascending order.
• chuck, annie, jan
• Correct! This will sort by the values in ascending order.
• annie, chuck, jan
• This will sort by the values in ascending order.
• jan, annie, chuck
• This will sort by the values in ascending order.

Q-10: What order do the keys print in after the following code is run?

counts = {'annie' : 42, 'chuck' : 1, 'jan' : 100}
items = counts.items()
sorted(items, key = lambda t: t[1])
for item in items:
    print(item[0])

• jan, chuck, annie
• This will print the keys in their current order since sorted returns a new list.
• chuck, annie, jan
• This will print the keys in their current order since sorted returns a new list.
• annie, chuck, jan
• Correct! This will print the keys in their current order since sorted returns a new list.
• jan, annie, chuck
• This will print the keys in their current order since sorted returns a new list.

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