Before you keep reading...

Runestone Academy can only continue if we get support from individuals like you. As a student you are well aware of the high cost of textbooks. Our mission is to provide great books to you for free, but we ask that you consider a $10 donation, more if you can or less if $10 is a burden.

Support Runestone Academy Today

Before you keep reading...

Making great stuff takes time and $$. If you appreciate the book you are reading now and want to keep quality materials free for other students please consider a donation to Runestone Academy. We ask that you consider a $10 donation, but if you can give more thats great, if $10 is too much for your budget we would be happy with whatever you can afford as a show of support.

Support Runestone Academy Today

Chapter 13 Exercises

1. Fix 7 problems in the code below so that it runs.

   score = 20 if score < 10 print("You can do better.") if score > 10: print(Good job!") if score > 20 print("Amazing"

   Add : at the end of line 2. Indent lines 3, 5, and 7. Add a " after the ( on line 5. Add a : on line 6. Add a ) at the end of line 7.

   score = 20 if score < 10: print("You can do better.") if score > 10: print("Good job!") if score > 20: print("Amazing")

   Show Comments

2. Fix the errors in the code so that it prints “Less than 5” when a number is less than 5 and “Greater than or equal to 5” when it is greater than or equal to 5.

   x = 4 if x > 5 print("Less than 5") if x =< 5 print("Greater than or equal to 5")

   Fix indentation on lines 3 and 4. Add colons after the if statements. Fix the conditions to match the words.

   x = 4 if x < 5: print("Less than 5") if x >= 5: print("Greater than or equal to 5")

   Show Comments

3. Fix 6 errors in the code below so that it works correctly.

   print(You are in front of a creepy door in a hallway.") prin("What do you want to do?") action = input ("Type: in, left, or right. Then click OK or press enter) if action == "in" print("You choose to go in.") print("The room is pitch black.") if action == "left": print("You choose to turn left.") print("A ghost appears at the end of the hall.") if action == "right": print("You choose to turn right.") print("A greenish light is visible in the distance.")

   Add a " after the ( on line 1. Change line 2 to print. Add a " before the ) on line 3. Add a : at the end of line 4. Indent lines 8 and 12.

   print("You are in front of a creepy door in a hallway.") print("What do you want to do?") action = input ("Type: in, left, or right. Then click OK or press enter") if action == "in": print("You choose to go in.") print("The room is pitch black.") if action == "left": print("You choose to turn left.") print("A ghost appears at the end of the hall.") if action == "right": print("You choose to turn right.") print("A greenish light is visible in the distance.")

   Show Comments

4. Complete the code to get user input, and make choices based off the input. The input should either be “in”, “left”, or “right”; make sure the user knows that.

   print("You are in front of a creepy door in a hallway.") print("What do you want to do?") userInput = if print("You choose to go in.") print("The room is pitch black.") if print("You choose to turn left.") print("A ghost appears at the end of the hall.") if print("You choose to turn right.") print("A greenish light is visible in the distance.")

   Complete the question asking for user input and complete the if statements.

   print("You are in front of a creepy door in a hallway.") print("What do you want to do?") userInput = input("Type: in, left, or right. Then click OK or press enter) if userInput == "in": print("You choose to go in.") print("The room is pitch black.") if userInput == "left": print("You choose to turn left.") print("A ghost appears at the end of the hall.") if userInput == "right": print("You choose to turn right.") print("A greenish light is visible in the distance.")

   Show Comments

5. Fix the code below to assign grades correctly using elif and else. You can assume the numbers are all correct.

   score = 80 if score >= 90: grade = "A" if score >= 80: grade = "B" if score >= 70: grade = "C" if score >= 60: grade = "D" if score < 60: grade = "E" print(grade)

   Change lines 4, 6, and 8 to elif. Change line 10 to else:.

   score = 80 if score >= 90: grade = "A" elif score >= 80: grade = "B" elif score >= 70: grade = "C" elif score >= 60: grade = "D" else: grade = "E" print(grade)

   Show Comments

6. The following code prints both statements, change it so that it only prints the first one when the age is less than 6.

   age = 4 if age < 6: print("You're in kindergarten") if age < 11: print("You're in elementary school")

   Use elif clause for the second one.

   age = 4 if age < 6: print("You're in kindergarten") elif age < 11: print("You're in elementary school")

   Show Comments

7. Change the code below to use elif and else rather than several ifs. Also fix it to print “Good job!” if the score is greater than 10 and less than or equal to 20 and “Amazing” if the score is over 20.

   score = 22 if score < 10: print("You can do better.") if score > 10: print("Good job!") if score > 20: print("Amazing")

   Change line 4 to elif score > 10 and score <= 20: and change line 6 to else:.

   score = 22 if score < 10: print("You can do better.") elif score > 10 and score <= 20: print("Good job!") else: print("Amazing")

   Show Comments

8. Complete the code so that it iterates through the list of numbers and prints positive, negative, or neither based off the integer.

   numbers = [-1,0,1] for x in numbers: if print("positive") elif print( else: print(

   Should check if x is greater than, less than, or equal to 0, and print the appropriate response.

   numbers = [-1,0,1] for x in numbers: if x > 0: print("positive") elif x < 0: print("negative") else: print("neither")

   Show Comments

9. Change the code below to use elif and else.

   num = input ("Type a number from 1 to 5. Then click OK or press enter") if num == "1": print("You will get a treat.") if num == "2": print("You will lose something.") if num == "3": print("You will meet a new friend.") if num == "4": print("You will catch a cold.") if num == "5": print("You will ace a test.")

   Change lines 4, 6, and 8 to elif and change line 10 to else.

   num = input ("Type a number from 1 to 5. Then click OK or press enter") if num == "1": print("You will get a treat.") elif num == "2": print("You will lose something.") elif num == "3": print("You will meet a new friend.") elif num == "4": print("You will catch a cold.") else: print("You will ace a test.")

   Show Comments

10. Fix the errors in the code and change it to use elif’s and else so that if the user’s score is greater than the high score, it prints “Good job!”, if it’s lower, print “Try again.”, and if it’s the same print “You tied the high score”.

    highScore = 10 userInput = Input("What's your score? (Give a number 1 - 20)") userInput = int(userInput) if userInput < 10 print(Good job!) if userInput > 10 print("Try again.") if userInput = 10 print("You tied the high score.")

    Fix indentation and add colons after the if clauses. Add quotes to strings, lowercase “input”, and fix the signs in the conditionals. Also replace the second and third conditions with elif and else.

    highScore = 10 userInput = input("What's your score? (Give me a number 1 -20)") userInput = int(userInput) if userInput > 10: print("Good job!") elif userInput < 10: print("Try again.") else: print("You tied the high score.")

    Show Comments

11. Change the following code to use elif and else instead.

    team1 = 20 team2 = 20 if (team1 < team2): print("team1 won") if (team2 > team1): print("team2 won") if (team2 == team1): print("team1 and team2 tied")

    Change line 5 to elif and line 7 to else.

    team1 = 20 team2 = 20 if (team1 < team2): print("team1 won") elif (team2 > team1): print("team2 won") else: print("team1 and team2 tied")

    Show Comments

12. Add statements to the code, so that if the user gives a number less than 5, you ask for the input again, and have another set of decision statements based off if the number is greater than, less than, or equal to 3.

    user = input("Give me a number") number = int(user) if number < 5: user2 = number2 = int(user2) if print("I love CS") elif print("CS is the best") else: print("I like CS better than food") else: print("Who else loves CS?")

    Complete as shown below.

    user = input("Give me a number") number = int(user) if number < 5: user2 = input("Give me a number") number2 = int(user2) if number2 > 3: print("I love CS") elif number2 < 3: print("CS is the best") else: print("I like CS better than food") else: print("Who else loves CS?")

    Show Comments

13. Change the code below to use only 1 if, 1 elif, and 1 else.

    state = "Georgia" if state == "Georgia": print("It's hot") if state == "Florida": print("It's hot") if state == "Alaska": print("It's cold") else: print("I don't know the weather")

    Combine the first 2 if statements by using an or. Change the third if statement into an elif.

    state = "Georgia" if state == "Georgia" or state == "Florida": print("It's hot") elif state == "Alaska": print("It's cold") else: print("I don't know the weather")

    Show Comments

14. Fix the code and change the statements so there are three sets of if and else and 2 elifs.

    if bikes > people: print("We should take the bikes.") if bikes < people: print("We should not take the bikes.") if bikes == people: print("We can't decide.") if vans > bikes: print("That's too many vans.") if vans < bikes: print("Maybe we could take the vans.") if vans == bikes: print("We still can't decide.") if people > vans: print("Alright, let's just take the vans.") if people <= vans: print("Fine, let's stay home then.")

    people = 30 bikes = 40 vans = 15 if bikes > people: print("We should take the bikes.") elif bikes < people: print("We should not take the bikes.") else: print("We can't decide.") if vans > bikes: print("That's too many vans.") elif vans < bikes: print("Maybe we could take the vans.") else: print("We still can't decide.") if people > vans: print("Alright, let's just take the vans.") else: print("Fine, let's stay home then.")

    Show Comments

15. Change the code below into a procedure that takes a number as a parameter and prints the quartile. Be sure to test each quartile.

    x = .25 if x <= .25: print("x is in the first quartile - x <= .25") if x <= .5 and x > .25: print("x is in the second quartile - .25 < x <= .5") if x <= .75 and x > .5: print("x is in the third quartile - .5 < x <= .75") if x > .75: print("x is in the fourth quartile - .75 < x <= 1")

    Create the procedure and pass the number. Test the procedure for each quartile.

    def printQuartile(x): if x <= .25: print("x is in the first quartile - x <= .25") if x <= .5 and x > .25: print("x is in the second quartile - .25 < x <= .5") if x <= .75 and x > .5: print("x is in the third quartile - .5 < x <= .75") if x > .75: print("x is in the fourth quartile - .75 < x <= 1") printQuartile(.25) printQuartile(0.3) printQuartile(0.5) printQuartile(0.75) printQuartile(0.8)

    Show Comments

16. Fix the code so that it prints only 1 thing for each age group and uses elif and else.

    age = 10 if age >= 18: print("adult") if age < 18: print("teen") if age < 13: print("pre-teen") if age < 10: print("kid") if age < 5: print("toddler") if age < 2: print("baby")

    Flip the order of the statments, and substitute elif and else clauses for everything but the first statement.

    age = 10 if age < 2: print("baby") elif age < 5: print("toddler") elif age < 10: print("kid") elif age < 13: print("pre-teen") elif age < 18: print("teen") else: print("adult")

    Show Comments

17. Write a function that will take a number as input and return a fortune as a string. Ask the user to pick a number to get the fortune before you call the function. Have at least 5 different fortunes. Use if, elif, and else.

    Define the function as shown below and be sure to test it.

    def getFortune(num): if num == "1": return("You will ace a test") elif num == "2": return("You will get hurt.") elif num == "3": return("You will meet a new friend.") elif num == "4": return("You will find a penny.") else: return("You will lose something.") num = input ("Type a number from 1 to 5. Then click OK or press enter") print(getFortune(num))

    Show Comments

18. Write a function that takes in a list of grades and returns the letter grade of the average (A is 90+, B is 80-89, C is 70-79, D is 60-69, F is 59 and below). Call the function and print the result.

    Iterate through the list to find the average then use if, elif, and else statements to determine the letter grade.

    def gradeAverage(aList): sum = 0 for x in aList: sum = sum + x avg = sum / len(aList) if avg >= 90: grade = "A" elif avg >= 80: grade = "B" elif avg >= 70: grade = "C" elif avg >= 60: grade = "D" else: grade = "F" return grade print(gradeAverage([80,90,90,80,100]))

    Show Comments

19. Write a procedure to tell an interactive story and let the user choose one of at least 3 options.

    Create a procedure as shown below. Call it to test it and print the result.

    def story(): print("You are in front of a creepy door in a hallway.") print("What do you want to do?") action = input ("Type: in, left, or right. Then click OK or press enter") if action == "in": print("You choose to go in.") print("The room is pitch black.") if action == "left": print("You choose to turn left.") print("A ghost appears at the end of the hall.") if action == "right": print("You choose to turn right.") print("A greenish light is visible in the distance.") story()

    Show Comments

20. Write code that iterates through number 1 - 20 and prints “Fizz” if it’s a multiple of 3, “Buzz” if it’s a multiple of 5, “FizzBuzz” if it’s a multiple of 3 and 5, and the number if it’s not a multiple of 3 or 5. It should only print one statement per number.

    Order of the first statement is important. Look below.

    for x in range (1,21): if x % 3 == 0 and x % 5 == 0: print("FizzBuzz") elif x % 3 == 0: print("Fizz") elif x % 5 == 0: print("Buzz") else: print(x)

    Show Comments

You have attempted of activities on this page