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Section 3.2 Negating Quantified Statements

In this section we will look at how to negate statements involving quantifiers.
If you look back at the Check your Understanding questions in Section 3.1, you should notice that both xD,P(x) and xD,P(x) were false, which means they are not negations of each other. Similarly, both xD,P(x) and xD,P(x) were true. In general, the two statements won’t necessarily have the same truth values, but the examples were chosen to make sure we can see that they are not negations of each other.

Negating Quantified Statements.

The negation of xD,P(x) is xD,P(x).
In notation:
(xD,P(x))xD,P(x).
The negation of xD,P(x) is xD,P(x).
In notation:
(xD,P(x))xD,P(x).
We can think of negation as switching the quantifier and negating P(x), but it will be really helpful if we can understand why this is the negation. Thinking about negating a “for all” statement, we need the statement to not be true for all things, which means it must be false for something, Thus, there exists something making P(x) true. Thinking about negating a “there exists” statement, we need there not to exist anything making P(x) true, which means P(x) must be false for everything. Thus, everything makes P(x) true.

Example 3.2.1. Negating a Quantified Statement.

Negate the statement: For all primes p, p is odd. Is this statement true or false?
Answer 1.
There exist a prime p such that p is not odd. The original statement is false, since we can find an even prime (p=2).
Negate the statement: There exists a real number x, such that x2<0. Is this statement true or false?
Answer 2.
For all real numbers x, x20. The original statement is false, since the negation is true.

Activity 3.2.1.

Write the negation of the following statements (in English).

(a)

For all integers n, n is an integer.

(b)

There exists an integer n, such that n2=5.
Many of our quantified statements may have predicates involving other logical connectives. So it is going to be important to remember how to negate "and"s, "or"s, and "if...then"s. The following summarizes the rules we have already seen for negating statements with connectives

Negations of Logical Statements.

  • AND statement.
    (pq)≡∼p q. This is DeMorgan’s Law.
  • OR statement.
    (pq)≡∼p q. This is DeMorgan’s Law.
  • IF...THEN statement.
    (pq)p q. The negation of a conditional is NOT a conditional.
  • Universal conditional.
    (xD,P(x)Q(x))xD,(P(x)Q(x))xD,P(x)Q(x)

Activity 3.2.2.

Write the negation of the following statements (in English).

(a)

There exists an integer n, such that 1<n<2.

(b)

For all real numbers x, if x>2 then x+5>7.

(c)

For all functions f, if f is continuous, then f is differentiable.
Recall from Section 2.2 the contapositive of pq is q→∼p. We can use this to define the contrapositive of a universal conditional statement.

Definition 3.2.2.

The universal conditional statement xD,P(x)Q(x) has contrapositive xD,Q(x)→∼P(x).
Similarly, the converse of pq is qp.

Definition 3.2.3.

The universal conditional statement xD,P(x)Q(x) has converse xD,Q(x)P(x).

Activity 3.2.3.

Consider the statement “For all real numbers x, if (x+1)(x2)>0 then x<1 or x>2.

(a)

Write the negation of the statement.

(b)

Write the contrapositive of the statement.

Activity 3.2.4.

Consider the statement “For all integers n, if n has a factor of 15, then n has a factor of 3 and n has a factor of 5.”

(a)

Write the negation of the statement.

(b)

Write the contrapositive of the statement.
The relationship between “for all” and “there exists” can be used to show some surprising things. What happens if our domain, D, has nothing in it? In particular, let D=, the empty set. Is xD,P(x) true or false? Well, let’s look at the negation: xD,P(x). Now the negation must be false since D has nothing in it, so there can’t exist something in D making P(x) true. Since the negation is false, the original statement is true! We say xD,P(x) is vacuously true.

Example 3.2.4. Vacuously True Statement.

Consider the statement “For all llamas, L, in Discrete Math, L is getting an A.” The negation is “There exists a llama, L, in Discrete Math, such that L is not getting an A.” Since no such llama exists, the negation is false. Making the original true. So every llama in Discrete is getting an A.
As one additional note, it can be helpful in deciding if your negation is correct by finding the truth value of both the original and the negation. They should have opposite values. Similarly, if you need to determine the truth value of a complex statement, it might be easier to find the truth value of the negation.

Activity 3.2.5.

Determine if each of the following statements are true or false. It may be helpful to look at the negations you founds in the above activities, Activity 3.2.1, Activity 3.2.2, Activity 3.2.3, and Activity 3.2.4.

(a)

For all integers n, n is an integer.

(b)

There exists an integer n, such that n2=5.

(c)

There exists an integer n, such that 1<n<2.

(d)

For all real numbers x, if x>2 then x+5>7.

(e)

For all functions f, if f is continuous, then f is differentiable.

(f)

For all real numbers x, if (x+1)(x2)>0 then x<1 or x>2.

(g)

For all integers n, if n has a factor of 15, then n has a factor of 3 and n has a factor of 5.

Reading Questions Check Your Understanding

1.

    Determine the negation of nZ,n>0.
  • nZ,n0.
  • nZ,n>0.
  • nZ,n0.
  • nZ,n>0.

2.

    Determine the negation of nZ, if n>0 then n3>0.
  • nZ, if n0 then n30
  • nZ, n0 and n30.
  • nZ, n>0 and n30.
  • nZ, if n0 then n30

3.

    Determine the negation of nZ, n>5 and n210.
  • nZ, n5 or n2>10.
  • nZ, n5 and n2>10.
  • nZ, n>5 or n210.
  • nZ, n>5 or n210.
  • nZ, n5 and n2>10.

4.

    Determine the negation of nZ, such that if n2>4 then n>2 or n<2.
  • nZ, if n24 then n2 or n2.
  • nZ, if n24 then 2n2.
  • nZ, n2>4 and 2n2.
  • nZ, n24 and 2n2.
  • nZ, n24 and n2 or n2.

5.

    Determine the contrapositive of nZ, if n>0 then n3>0.
  • nZ, if n30 then n0.
  • nZ, if n0 then n30.
  • nZ, if n0 then n30.
  • nZ, if n30 then n0.

Exercises Exercises

1.

Which of the following is a negation for “All discrete math students are athletic”? More than one answer may be correct.
  1. There is a discrete math student who is nonathletic.
  2. All discrete math students are nonathletic.
  3. There is an athletic person who is a discrete math student.
  4. No discrete math students are athletic.
  5. Some discrete math students are nonathletic.
  6. No athletic people are discrete math students.

2.

Write an informal negation for each of the following statements. Be careful to avoid negations that are ambiguous.
  1. All dogs are friendly.
  2. All people are happy.
  3. Some apples are red.
  4. Some teams are undefeated.

3.

Write a negation for each of the following statements.
  1. Any valid argument has a true conclusion.
  2. Every real number is positive, negative, or zero.

4.

Write the negation of each of the statements.
  1. real numbers x, if x>3 then x2>9.
  2. nZ, if n is prime then n is odd or n=2.
  3. integers n, if n is divisible by 6, then n is divisible by 2 and n is divisible by 3.

5.

Determine whether the proposed negation is correct. If it is not, write a correct negation.
Statement: The sum of any two irrational numbers is irrational.
Proposed negation: The sum of any two irrational numbers is rational.

6.

Determine whether the proposed negation is correct. If it is not, write a correct negation.
Statement: For all integers n, if n2 is even then n is even.
Proposed negation: For all integers n, if n2 is even, then n is not even.

7.

Consider the following sequence of digits: 2300204. A person claims that all of the 1’s in the sequence are to the left of all of the 0’s in the sequence. Is this true? Justify your answer.
Hint.
Write the claim formally and write a formal negation for it. Is the negation true or false?
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